xxq250/Nasal-Interpreter
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Valk Richard Li
2020-12-17 00:14:22 +08:00
parent 19ce1c5f34
commit ae16f36baa
3 changed files with 19 additions and 23 deletions
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nasal.h
+8 -8
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@@ -25,10 +25,10 @@
check if a string can be converted to a number
if this string cannot be converted to a number,it will return nan
*/
inline double hex_to_double(std::string str,int len)
inline double hex_to_double(std::string str)
{
double ret=0;
for(int i=2;i<len;++i)
for(int i=2;str[i];++i)
{
ret*=16;
if('0'<=str[i] && str[i]<='9')
@@ -42,10 +42,10 @@ inline double hex_to_double(std::string str,int len)
}
return ret;
}
inline double oct_to_double(std::string str,int len)
inline double oct_to_double(std::string str)
{
double ret=0;
for(int i=2;i<len;++i)
for(int i=2;str[i];++i)
{
ret*=8;
if('0'<=str[i] && str[i]<='8')
@@ -106,10 +106,10 @@ double trans_string_to_number(std::string str)
is_negative=(str[0]=='-'?-1:1);
str=str.substr(1,len--);
}
if(len>2 && str[0]=='0' && str[1]=='x')
ret_num=hex_to_double(str,len);
else if(len>2 && str[0]=='0' && str[1]=='o')
ret_num=oct_to_double(str,len);
if(len>1 && str[0]=='0' && str[1]=='x')
ret_num=hex_to_double(str);
else if(len>1 && str[0]=='0' && str[1]=='o')
ret_num=oct_to_double(str);
else
ret_num=dec_to_double(str,len);
return is_negative*ret_num;