49 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			Fortran
		
	
	
	
			
		
		
	
	
			49 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			Fortran
		
	
	
	
|       subroutine daxpyf(n,da,dx,incx,dy,incy)
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| c
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| c     constant times a vector plus a vector.
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| c     uses unrolled loops for increments equal to one.
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| c     jack dongarra, linpack, 3/11/78.
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| c     modified 12/3/93, array(1) declarations changed to array(*)
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| c
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|       double precision dx(*),dy(*),da
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|       integer i,incx,incy,ix,iy,m,mp1,n
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| c
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|       if(n.le.0)return
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|       if (da .eq. 0.0d0) return
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|       if(incx.eq.1.and.incy.eq.1)go to 20
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| c
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| c        code for unequal increments or equal increments
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| c          not equal to 1
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| c
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|       ix = 1
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|       iy = 1
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|       if(incx.lt.0)ix = (-n+1)*incx + 1
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|       if(incy.lt.0)iy = (-n+1)*incy + 1
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|       do 10 i = 1,n
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|         dy(iy) = dy(iy) + da*dx(ix)
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|         ix = ix + incx
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|         iy = iy + incy
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|    10 continue
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|       return
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| c
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| c        code for both increments equal to 1
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| c
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| c
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| c        clean-up loop
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| c
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|    20 m = mod(n,4)
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|       if( m .eq. 0 ) go to 40
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|       do 30 i = 1,m
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|         dy(i) = dy(i) + da*dx(i)
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|    30 continue
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|       if( n .lt. 4 ) return
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|    40 mp1 = m + 1
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|       do 50 i = mp1,n,4
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|         dy(i) = dy(i) + da*dx(i)
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|         dy(i + 1) = dy(i + 1) + da*dx(i + 1)
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|         dy(i + 2) = dy(i + 2) + da*dx(i + 2)
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|         dy(i + 3) = dy(i + 3) + da*dx(i + 3)
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|    50 continue
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|       return
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|       end
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