245 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Fortran
		
	
	
	
			
		
		
	
	
			245 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Fortran
		
	
	
	
*> \brief \b CPBEQU
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*
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*  =========== DOCUMENTATION ===========
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*
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* Online html documentation available at
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*            http://www.netlib.org/lapack/explore-html/
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*
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*> \htmlonly
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*> Download CPBEQU + dependencies
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*> <a href="http://www.netlib.org/cgi-bin/netlibfiles.tgz?format=tgz&filename=/lapack/lapack_routine/cpbequ.f">
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*> [TGZ]</a>
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*> <a href="http://www.netlib.org/cgi-bin/netlibfiles.zip?format=zip&filename=/lapack/lapack_routine/cpbequ.f">
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*> [ZIP]</a>
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*> <a href="http://www.netlib.org/cgi-bin/netlibfiles.txt?format=txt&filename=/lapack/lapack_routine/cpbequ.f">
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*> [TXT]</a>
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*> \endhtmlonly
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*
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*  Definition:
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*  ===========
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*
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*       SUBROUTINE CPBEQU( UPLO, N, KD, AB, LDAB, S, SCOND, AMAX, INFO )
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*
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*       .. Scalar Arguments ..
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*       CHARACTER          UPLO
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*       INTEGER            INFO, KD, LDAB, N
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*       REAL               AMAX, SCOND
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*       ..
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*       .. Array Arguments ..
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*       REAL               S( * )
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*       COMPLEX            AB( LDAB, * )
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*       ..
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*
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*
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*> \par Purpose:
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*  =============
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*>
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*> \verbatim
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*>
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*> CPBEQU computes row and column scalings intended to equilibrate a
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*> Hermitian positive definite band matrix A and reduce its condition
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*> number (with respect to the two-norm).  S contains the scale factors,
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*> S(i) = 1/sqrt(A(i,i)), chosen so that the scaled matrix B with
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*> elements B(i,j) = S(i)*A(i,j)*S(j) has ones on the diagonal.  This
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*> choice of S puts the condition number of B within a factor N of the
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*> smallest possible condition number over all possible diagonal
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*> scalings.
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*> \endverbatim
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*
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*  Arguments:
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*  ==========
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*
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*> \param[in] UPLO
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*> \verbatim
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*>          UPLO is CHARACTER*1
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*>          = 'U':  Upper triangular of A is stored;
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*>          = 'L':  Lower triangular of A is stored.
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*> \endverbatim
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*>
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*> \param[in] N
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*> \verbatim
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*>          N is INTEGER
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*>          The order of the matrix A.  N >= 0.
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*> \endverbatim
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*>
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*> \param[in] KD
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*> \verbatim
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*>          KD is INTEGER
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*>          The number of superdiagonals of the matrix A if UPLO = 'U',
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*>          or the number of subdiagonals if UPLO = 'L'.  KD >= 0.
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*> \endverbatim
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*>
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*> \param[in] AB
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*> \verbatim
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*>          AB is COMPLEX array, dimension (LDAB,N)
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*>          The upper or lower triangle of the Hermitian band matrix A,
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*>          stored in the first KD+1 rows of the array.  The j-th column
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*>          of A is stored in the j-th column of the array AB as follows:
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*>          if UPLO = 'U', AB(kd+1+i-j,j) = A(i,j) for max(1,j-kd)<=i<=j;
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*>          if UPLO = 'L', AB(1+i-j,j)    = A(i,j) for j<=i<=min(n,j+kd).
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*> \endverbatim
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*>
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*> \param[in] LDAB
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*> \verbatim
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*>          LDAB is INTEGER
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*>          The leading dimension of the array A.  LDAB >= KD+1.
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*> \endverbatim
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*>
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*> \param[out] S
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*> \verbatim
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*>          S is REAL array, dimension (N)
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*>          If INFO = 0, S contains the scale factors for A.
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*> \endverbatim
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*>
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*> \param[out] SCOND
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*> \verbatim
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*>          SCOND is REAL
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*>          If INFO = 0, S contains the ratio of the smallest S(i) to
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*>          the largest S(i).  If SCOND >= 0.1 and AMAX is neither too
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*>          large nor too small, it is not worth scaling by S.
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*> \endverbatim
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*>
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*> \param[out] AMAX
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*> \verbatim
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*>          AMAX is REAL
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*>          Absolute value of largest matrix element.  If AMAX is very
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*>          close to overflow or very close to underflow, the matrix
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*>          should be scaled.
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*> \endverbatim
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*>
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*> \param[out] INFO
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*> \verbatim
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*>          INFO is INTEGER
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*>          = 0:  successful exit
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*>          < 0:  if INFO = -i, the i-th argument had an illegal value.
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*>          > 0:  if INFO = i, the i-th diagonal element is nonpositive.
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*> \endverbatim
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*
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*  Authors:
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*  ========
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*
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*> \author Univ. of Tennessee
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*> \author Univ. of California Berkeley
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*> \author Univ. of Colorado Denver
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*> \author NAG Ltd.
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*
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*> \date December 2016
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*
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*> \ingroup complexOTHERcomputational
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*
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*  =====================================================================
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      SUBROUTINE CPBEQU( UPLO, N, KD, AB, LDAB, S, SCOND, AMAX, INFO )
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*
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*  -- LAPACK computational routine (version 3.7.0) --
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*  -- LAPACK is a software package provided by Univ. of Tennessee,    --
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*  -- Univ. of California Berkeley, Univ. of Colorado Denver and NAG Ltd..--
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*     December 2016
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*
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*     .. Scalar Arguments ..
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      CHARACTER          UPLO
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      INTEGER            INFO, KD, LDAB, N
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      REAL               AMAX, SCOND
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*     ..
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*     .. Array Arguments ..
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      REAL               S( * )
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      COMPLEX            AB( LDAB, * )
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*     ..
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*
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*  =====================================================================
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*
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*     .. Parameters ..
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      REAL               ZERO, ONE
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      PARAMETER          ( ZERO = 0.0E+0, ONE = 1.0E+0 )
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*     ..
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*     .. Local Scalars ..
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      LOGICAL            UPPER
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      INTEGER            I, J
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      REAL               SMIN
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*     ..
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*     .. External Functions ..
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      LOGICAL            LSAME
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      EXTERNAL           LSAME
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*     ..
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*     .. External Subroutines ..
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      EXTERNAL           XERBLA
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*     ..
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*     .. Intrinsic Functions ..
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      INTRINSIC          MAX, MIN, REAL, SQRT
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*     ..
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*     .. Executable Statements ..
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*
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*     Test the input parameters.
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*
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      INFO = 0
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      UPPER = LSAME( UPLO, 'U' )
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      IF( .NOT.UPPER .AND. .NOT.LSAME( UPLO, 'L' ) ) THEN
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         INFO = -1
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      ELSE IF( N.LT.0 ) THEN
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         INFO = -2
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      ELSE IF( KD.LT.0 ) THEN
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         INFO = -3
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      ELSE IF( LDAB.LT.KD+1 ) THEN
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         INFO = -5
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      END IF
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      IF( INFO.NE.0 ) THEN
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         CALL XERBLA( 'CPBEQU', -INFO )
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         RETURN
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      END IF
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*
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*     Quick return if possible
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*
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      IF( N.EQ.0 ) THEN
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         SCOND = ONE
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         AMAX = ZERO
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         RETURN
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      END IF
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*
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      IF( UPPER ) THEN
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         J = KD + 1
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      ELSE
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         J = 1
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      END IF
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*
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*     Initialize SMIN and AMAX.
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*
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      S( 1 ) = REAL( AB( J, 1 ) )
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      SMIN = S( 1 )
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      AMAX = S( 1 )
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*
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*     Find the minimum and maximum diagonal elements.
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*
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      DO 10 I = 2, N
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         S( I ) = REAL( AB( J, I ) )
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         SMIN = MIN( SMIN, S( I ) )
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         AMAX = MAX( AMAX, S( I ) )
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   10 CONTINUE
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*
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      IF( SMIN.LE.ZERO ) THEN
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*
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*        Find the first non-positive diagonal element and return.
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*
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         DO 20 I = 1, N
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            IF( S( I ).LE.ZERO ) THEN
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               INFO = I
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               RETURN
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            END IF
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   20    CONTINUE
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      ELSE
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*
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*        Set the scale factors to the reciprocals
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*        of the diagonal elements.
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*
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         DO 30 I = 1, N
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            S( I ) = ONE / SQRT( S( I ) )
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   30    CONTINUE
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*
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*        Compute SCOND = min(S(I)) / max(S(I))
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*
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         SCOND = SQRT( SMIN ) / SQRT( AMAX )
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      END IF
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      RETURN
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*
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*     End of CPBEQU
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*
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      END
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