37 lines
		
	
	
		
			905 B
		
	
	
	
		
			Fortran
		
	
	
	
			
		
		
	
	
			37 lines
		
	
	
		
			905 B
		
	
	
	
		
			Fortran
		
	
	
	
|       double complex function zdotuf(n,zx,incx,zy,incy)
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| c
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| c     forms the dot product of two vectors.
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| c     jack dongarra, 3/11/78.
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| c     modified 12/3/93, array(1) declarations changed to array(*)
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| c
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|       double complex zx(*),zy(*),ztemp
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|       integer i,incx,incy,ix,iy,n
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|       ztemp = (0.0d0,0.0d0)
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|       zdotuf = (0.0d0,0.0d0)
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|       if(n.le.0)return
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|       if(incx.eq.1.and.incy.eq.1)go to 20
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| c
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| c        code for unequal increments or equal increments
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| c          not equal to 1
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| c
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|       ix = 1
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|       iy = 1
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|       if(incx.lt.0)ix = (-n+1)*incx + 1
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|       if(incy.lt.0)iy = (-n+1)*incy + 1
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|       do 10 i = 1,n
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|         ztemp = ztemp + zx(ix)*zy(iy)
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|         ix = ix + incx
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|         iy = iy + incy
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|    10 continue
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|       zdotuf = ztemp
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|       return
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| c
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| c        code for both increments equal to 1
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| c
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|    20 do 30 i = 1,n
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|         ztemp = ztemp + zx(i)*zy(i)
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|    30 continue
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|       zdotuf = ztemp
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|       return
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|       end
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