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Allow to force the number of parallel make job 

This is particularly useful when using distcc
This commit is contained in:
Jerome Robert 2015-12-28 19:28:42 +01:00
parent b9b52c295d
commit ba024fcfc0
3 changed files with 11 additions and 1 deletions
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4
Makefile.rule
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@ -108,6 +108,10 @@ NO_AFFINITY = 1
# Don't use parallel make. # Don't use parallel make.
# NO_PARALLEL_MAKE = 1 # NO_PARALLEL_MAKE = 1
# Force number of make jobs. The default is the number of logical CPU of the host.
# This is particularly useful when using distcc
# MAKE_NB_JOBS = 2
# If you would like to know minute performance report of GotoBLAS. # If you would like to know minute performance report of GotoBLAS.
# FUNCTION_PROFILE = 1 # FUNCTION_PROFILE = 1

4
Makefile.system
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@ -139,6 +139,10 @@ NO_PARALLEL_MAKE=0
endif endif
GETARCH_FLAGS += -DNO_PARALLEL_MAKE=$(NO_PARALLEL_MAKE) GETARCH_FLAGS += -DNO_PARALLEL_MAKE=$(NO_PARALLEL_MAKE)
ifdef MAKE_NB_JOBS
GETARCH_FLAGS += -DMAKE_NB_JOBS=$(MAKE_NB_JOBS)
endif
ifeq ($(HOSTCC), loongcc) ifeq ($(HOSTCC), loongcc)
GETARCH_FLAGS += -static GETARCH_FLAGS += -static
endif endif

4
getarch.c
View File

@ -998,7 +998,9 @@ int main(int argc, char *argv[]){
#endif #endif
#endif #endif
#if NO_PARALLEL_MAKE==1 #ifdef MAKE_NB_JOBS
printf("MAKE += -j %d\n", MAKE_NB_JOBS);
#elif NO_PARALLEL_MAKE==1
printf("MAKE += -j 1\n"); printf("MAKE += -j 1\n");
#else #else
#ifndef OS_WINDOWS #ifndef OS_WINDOWS