chenyh
/
vRp.CD2g_test
1
0
Fork 0
Code Issues Pull Requests 1 Actions Packages Projects Releases Wiki Activity

fix: 修复 space.RoomManager.AssumeControl 函数编译错误的问题

This commit is contained in:
kercylan98 2023-12-23 18:12:07 +08:00
parent f52d73e20e
commit 3f099e6f8e
1 changed files with 1 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

2
game/space/room_manager.go
View File

@ -25,7 +25,7 @@ type RoomManager[EntityID comparable, RoomID comparable, Entity generic.IdR[Enti
// AssumeControl 将房间控制权交由 RoomManager 接管，返回 RoomController 实例
// - 当任何房间需要被 RoomManager 管理时，都应该调用该方法获取到 RoomController 实例后进行操作
// - 房间被接管后需要在释放房间控制权时调用 RoomController.Destroy 方法，否则将会导致 RoomManager 一直持有房间资源
func (rm *RoomManager[EntityID, RoomID, Entity, Room]) AssumeControl(room Room, options ...*RoomControllerOptions) *RoomController[EntityID, RoomID, Entity, Room] {
func (rm *RoomManager[EntityID, RoomID, Entity, Room]) AssumeControl(room Room, options ...*RoomControllerOptions[EntityID, RoomID, Entity, Room]) *RoomController[EntityID, RoomID, Entity, Room] {
controller := newRoomController(rm, room, mergeRoomControllerOptions(options...))
rm.OnRoomAssumeControlEvent(controller)
return controller